Knights and Knaves is a type of logic puzzle where some characters can only answer questions truthfully, and others only falsely. The name was coined by Raymond Smullyan in his 1978 work What Is the Name of This Book?^{[1]}
The puzzles are set on a fictional island where all inhabitants are either knights, who always tell the truth, or knaves, who always lie. The puzzles involve a visitor to the island who meets small groups of inhabitants. Usually the aim is for the visitor to deduce the inhabitants' type from their statements, but some puzzles of this type ask for other facts to be deduced. The puzzle may also be to determine a yesno question which the visitor can ask in order to discover a particular piece of information.
One of Smullyan's examples of this type of puzzle involves three inhabitants referred to as A, B and C. The visitor asks A what type he is, but does not hear A's answer. B then says "A said that he is a knave" and C says "Don't believe B; he is lying!"^{[2]} To solve the puzzle, note that no inhabitant can say that he is a knave. Therefore, B's statement must be untrue, so he is a knave, making C's statement true, so he is a knight. Since A's answer invariably would be "I'm a knight", it is not possible to determine whether A is a knight or knave from the information provided.
Maurice Kraitchik presents the same puzzle in 1953 book Mathematical Recreations, where two groups on a remote island – the Arbus and the Bosnins – either lie or tell the truth, and respond to the same question as above.^{[3]}
In some variations, inhabitants may also be alternators, who alternate between lying and telling the truth, or normals, who can say whatever they want.^{[2]} A further complication is that the inhabitants may answer yes/no questions in their own language, and the visitor knows that "bal" and "da" mean "yes" and "no" but does not know which is which. These types of puzzles were a major inspiration for what has become known as "the hardest logic puzzle ever".
Contents

Examples 1

Both knaves 1.1

Same or different kinds 1.2

Fork in the road 1.3

References 2

External links 3
Examples
A large class of elementary logical puzzles can be solved using the laws of Boolean algebra and logic truth tables. Familiarity with boolean algebra and its simplification process will help with understanding the following examples.
John and Bill are residents of the island of knights and knaves.
Both knaves
John says "We are both knaves."
In this case, John is a knave and Bill is a knight. John's statement cannot be true because a knave admitting to being a knave would be the same as a liar telling the lie "I am a liar", which is known as the liar paradox. Since John is a knave this means he must have been lying about them both being knaves, and so Bill is a knight.
Same or different kinds
John says "We are the same kind.", but Bill says "We are of different kinds."
In this scenario they are making contradictory statements and so one must be a knight and one must be a knave. Since that is exactly what Bill said, Bill must be the knight, and John is the knave.
Fork in the road
"John and Bill are standing at a fork in the road. John is standing in front of the left road, and Bill is standing in front of the right road. One of them is a knight and the other a knave, but you don't know which. You also know that one road leads to Death, and the other leads to Freedom. By asking one yes–no question, can you determine the road to Freedom?"
This is perhaps the most famous rendition of this type of puzzle. This version of the puzzle was further popularised by a scene in the 1986 fantasy film, Labyrinth, in which a character finds herself faced with two doors each guarded by a knight. One door leads to the castle at the centre of the labyrinth, and one to certain doom. It had also appeared some ten years previously, in a very similar form, in the Doctor Who story Pyramids of Mars.
There are several ways to find out which way leads to freedom. All can be determined by using Boolean algebra and a truth table.
One solution is to ask of either man, "Would you answer "Yes" if I asked you "Does your path lead to freedom?"" If the man says "Yes", then the path leads to freedom, if he says "No", then it does not. The reasoning is as follows:

A knight would answer the question "Does your path lead to freedom?" with 'Yes' if his path led to freedom and 'No' otherwise. He would also be truthful about whether this would be his answer. This means we can rely on the knight to say "Yes" to saying "Yes" when his path leads to freedom and "No" to saying "Yes" when it is not.

On the other hand, we know a knave will lie about whether his path leads to freedom. Fortunately, he will also lie about whether he will lie to that question. This means, when his path leads to freedom, he will say "Yes" to "Yes" just the same as a knight would, because in the knaves case it would be a lie. Similarly he would say "No" to saying "Yes" as that would be a lie too. As a result, the knave can also be relied upon to answer "Yes" only when his path leads to freedom and "No" otherwise.
This solution uses a known truth, specifically that the knight must tell the truth and the knave must lie, in the question we ask so that we can be sure of the validity of the answer. We can use this same technique to find out any information either man knows. Notably, if all we want to know is whether a man is a knight or a knave, you can test this by simply asking "Is a truth, true?". As a truth is always true, this is a tautology and hence a known truth which we can test against the answer they give.
References

^ George Boolos, John P. Burgess, Richard C. Jeffrey, Logic, logic, and logic (Harvard University Press, 1999).

^ ^{a} ^{b}

^
External links

A note on some philosophical implications of the Knights and Knaves puzzle for the concept of knowability

A complete list and analysis of Knight, Knave, and Spy puzzles, where spies are able to lie or tell the truth.
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